分層領域模型

DO(Data Object)：與數據庫表結構一一對應，通過DAO層向上傳輸數據源對象。
DTO(Data Transfer Object)：數據傳輸對向，Service和Manager向外傳輸的對象。
BO(Business Object)：業務對象。可以由Service層輸出的封裝業務邏輯對象。
VO(Value Object)：顯示顯對象，通常是web向模板渲染引擎層傳輸對象。

用docker啟動redis服務

1、先至docker hub上找到redis頁面
https://hub.docker.com/_/redis/

2、依網頁上的指令pull redis
開啟Terminal，輸入「docker pull redis」

3、找到image id
輸入「docker images」

4、啟動redis
輸入「docker run --name redis -d -p 6379:6379 ${imageID}」
指令中的${imageID}記得要換成自己的image id，像圖片中的redis image id是1aa84b1b434e
所以我本機輸入的指令為「docker run --name redis -d -p 6379:6379 1aa84b1b434e」

Reference:
https://hub.docker.com/_/redis/
http://stackoverflow.com/questions/31889163/cannot-connect-to-redis-running-as-container-with-boot2docker

Mac安裝docker-compose

1、安裝setuptools
輸入「brew install python」

2、透過easy_install安裝pip
輸入「sudo easy_install pip」

3、透過pip安裝docker-compose
輸入「pip install docker-compose」

4、驗証docker-compose是否安裝成功
輸入「docker-compose」

Reference:
http://docs.python-guide.org/en/latest/starting/install/osx/
https://docs.docker.com/compose/install/

LeetCode - 371. Sum of Two Integers

Question:

Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -.

Example:
Given a = 1 and b = 2, return 3.

https://leetcode.com/problems/sum-of-two-integers/

Solution:

public class Solution {
    public int getSum(int a, int b) {
        return a+b;
    }
}

LeetCode - 374. Guess Number Higher or Lower

Question:

We are playing the Guess Game. The game is as follows:

I pick a number from 1 to n. You have to guess which number I picked.

Every time you guess wrong, I'll tell you whether the number is higher or lower.

You call a pre-defined API guess(int num) which returns 3 possible results (-1, 1, or 0):

https://leetcode.com/problems/guess-number-higher-or-lower/

Solution:

public class Solution extends GuessGame {
    
    public int guessNumber(int n) {
        Long R = new Long(n);
  Long L = 1L;
   
  if(R!=L){
   while(R>=L){
    Long mid = ((L+R)>>1);

    int result = guess(mid.intValue());
    //System.out.println("mid:" + mid + " ,result:" + result);
    if(result ==1){
     L = mid+1;
     
    }else if(result ==-1){
     R = mid-1;
    }else{
        return mid.intValue();
    }
   }
  }else{
      return R.intValue();
  }
  
  
  return L.intValue();
  
 }
}

LeetCode - 20. Valid Parentheses

Question:

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.

The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]" are not.

https://leetcode.com/problems/valid-parentheses/

Solution:

public class Solution {
    public boolean isValid(String s) {
        Stack<Character> stack = new Stack<Character>();
  
  char[] array = s.toCharArray();
  if (array.length % 2 != 0) {
   return false;
  }
  
  for(int i =0;i<array.length;i++){
   char c = array[i];
   if(c=='(' || c=='[' || c=='{'){
    stack.push(c);
    continue;
   }
   
   if(stack.isEmpty()==true){
    return false;
   }
   
   if(c==')'){
    if (stack.pop()!='(')
     return false;
   }else if(c==']'){
    if(stack.pop()!='[')
     return false;
   }else if(c=='}'){
    if(stack.pop()!='{')
     return false;
   }else{
    return false;
   }
  }
  
  if(stack.isEmpty()==false){
   return false;
  }else{
   return true;
  }
    }
}

在Mac上安裝Docker

關於Docker就不多說了，Docker現在出了Docker for Mac Beta
因此就不用再使用Docker Toolbox了
下載位置：https://docs.docker.com/docker-for-mac/

1、安裝非常簡單，從左邊拉到右邊就好了


2、安裝後執行，就可以在右上角看到執行中的圖示

3、就開始開終端機開始使用docker了，用「docker --version」確認版本資訊

4、安裝nginx，輸入指令「docker run -d -p 80:80 --name webserver nginx」

5、打開瀏覽器輸入「http://localhost/」就可以看到已經建立nginx服務了

Reference:
https://docs.docker.com/docker-for-mac/